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Home/ Questions/Q 4381898
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T12:42:32+00:00 2026-05-21T12:42:32+00:00

I have an NSMutableArray called container, and a NSMutableArray called temp. To make temp,

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I have an NSMutableArray called container, and a NSMutableArray called temp. To make temp, i have:

temp = container;

Now whenever i change something in temp, for example:

[temp replaceObjectAtIndex:1 withObject:[NSNumber numberWithFloat:0.9f]];

It changes temp, and also changes the value in container too. Why is this? And how can i stop it?

EDIT: Ok, i changed it to temp = [[container mutableCopy] autorelease]; as suggested

Now the problem is that this line:

[temp replaceObjectAtIndex:1 withObject:[NSNumber numberWithFloat:0.9f]];

still changes the value in container.

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  1. Editorial Team
    Editorial Team
    2026-05-21T12:42:32+00:00Added an answer on May 21, 2026 at 12:42 pm

    You’re just setting temp to share the same pointer as container.

    To get a true (independent) copy of container use this:

    NSMutableArray *temp = [[container mutableCopy] autorelease];
    

    Objective-C (being an object oriented derivative of C) uses C pointers for object variables (that’s the * in NSMutableArray *container).

    And a c pointer simply points to an address in memory. So if you were to set temp to the same value as container via temp = container; you just assigning temp the same address as container is already pointing at. Changing either of both will thus also change the other. Or more correct: you’re actually just changing one of them. It just looks like you’re changing both, but in fact you’re just having two pointers pointing at the same object instance, whch is being changed.

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