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Home/ Questions/Q 6771153
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T15:23:53+00:00 2026-05-26T15:23:53+00:00

I have an object, data , that may or may not contain the members

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I have an object, data, that may or may not contain the members site_with_same_coords and/or site_with_same_name. I test for these and if one or both exist, I alerts to the user:

if (data.site_with_same_coords){
    var SameCoordsExists = true;
    same_coords_message = 'The site ';
    same_coords_message += data.site_with_same_coords.name;
    same_coords_message += 'already already exists in the location you have indicated';
}

if (data.site_with_same_name){
    var SameNameExists = true;
    same_name_message = 'The site ';
    same_name_message += data.site_with_same_name.name;
    same_name_message += 'already already exists in a differnt location from the one you have indicated';
}

if (SameCoordsExists && SameNameExists){
    if(data.site_with_same_name.id != data.site_with_same_coords.id){
        alert(same_coords_message + '\n' + same_name_message);
    }else if (SameCoordsExists){
        alert(same_coords_message);
    }
    }else if (SameNameExists){
        alert(same_name_message);
    }
}

Is there a better way of doing this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T15:23:54+00:00Added an answer on May 26, 2026 at 3:23 pm

    Sure, you could put them in an array and join them:

    var messages = [];
    
    if(data.site_with_same_coords) {
        messages.push('The site ' + data.site_with_same_coords.name + ' already exists in the location you have indicated');
    }
    
    if(data.site_with_same_name && !(data.site_with_same_coords && data.site_with_same_name.id === data.site_with_same_coords.id)) {
        messages.push('The site ' + data.site_with_same_name.name + ' already exists in a different location from the one you have indicated');
    }
    
    alert(messages.join('\n'));
    

    Also, wouldn’t the user be a bit confused if they received the message:

    The site some_site already exists in the location you have indicated
    The site some_other_site already exists in a different location from the one you have indicated

    ? Just a thought.

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