Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 925289
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T19:29:46+00:00 2026-05-15T19:29:46+00:00

I have an object graph that contains a cycle. How do I get JAXB

  • 0

I have an object graph that contains a cycle. How do I get JAXB to handle this? I tried using the @XmlTransient annotation in the child class but the JAXB marshaller still detects the cycle.

@Entity
@XmlRootElement
public class Contact {

    @Id
    private Long contactId;

    @OneToMany(mappedBy = "contact")
    private List<ContactAddress> addresses;

...

}

@Entity
@XmlRootElement
public class ContactAddress {

    @Id
    private Long contactAddressId;

    @ManyToOne
    @JoinColumn(name = "contact_id")
    private Contact contact;

    private String address;

...

}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T19:29:47+00:00Added an answer on May 15, 2026 at 7:29 pm

    The good thing about using JAXB is that it is a standard runtime with multiple implementations (just like JPA).

    If you use EclipseLink JAXB (MOXy) then you have many extensions available to you for handling JPA entities including bi-directional relationships. This is done using the MOXy @XmlInverseReference annotation. It acts similar to @XmlTransient on the marshal and populates the target-to-source relationship on the unmarshal.

    http://wiki.eclipse.org/EclipseLink/Examples/MOXy/JPA/Relationships

    @Entity 
    @XmlRootElement 
    public class Contact { 
    
        @Id 
        private Long contactId; 
    
        @OneToMany(mappedBy = "contact") 
        private List<ContactAddress> addresses; 
    
    ... 
    
    } 
    
    @Entity 
    @XmlRootElement 
    public class ContactAddress { 
    
        @Id 
        private Long contactAddressId; 
    
        @ManyToOne 
        @JoinColumn(name = "contact_id") 
        @XmlInverseReference(mappedBy="addresses")
        private Contact contact; 
    
        private String address; 
    
    ... 
    
    } 
    

    Other extensions are available including support for composite keys & embedded key classes.

    To specify the EcliseLink MOXy JAXB implementation you need to include a jaxb.properties file in with your model classes (i.e. Contract) with the following entry:

    javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

No related questions found

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.