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Home/ Questions/Q 8405597
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T22:53:18+00:00 2026-06-09T22:53:18+00:00

I have an object in Javascript: function MyObject(aField) { this.field = aField; } MyObject.prototype.aFunction

  • 0

I have an object in Javascript:

function MyObject(aField) {
    this.field = aField;
}

MyObject.prototype.aFunction = function() {
    return this.field;
}

Then

var anInstance = new MyObject("blah");
var s = anInstance.aFunction();

this works fine, but if I pass the function to another function:

callLater(anInstance.aFunction);

I don’t control callLater and it’s minified, but it seems that it’s calling aFunction using call() or apply(). Therefore, this points to another object and field is undefined.

What’s the best practice to avoid this situation I’m facing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T22:53:19+00:00Added an answer on June 9, 2026 at 10:53 pm

    That’s because you lost the value of this Try this instead:

    callLater(function() { anInstance.aFunction() });
    

    Explaination, Think of it this way

    function MyObject(aField) {
        this.field = aField;
    }
    function MyObject2(aField) {
        this.field = aField;
    }
    MyObject.prototype.aFunction = someFunct;
    MyObject2.prototype.aFunction = someFunct;
    

    Now what does someFunct belong to?

    Well try doing MyObject.prototype.aFunction === MyObject2.prototype.aFunction it’ll be true!

    You see the problem Therefore it needs to be called from the class and not just referenced by value.

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