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Home/ Questions/Q 8841139
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T10:38:19+00:00 2026-06-14T10:38:19+00:00

I have an object LinkFinder that I’m having throw an exception if it gets

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I have an object “LinkFinder” that I’m having throw an exception if it gets a malformed URL, but I don’t like the idea of using System.out and just printing an error. Instead of the constructor returning the initialized object, can I force it to return null or something?

private URL url;

//constructor in question
public LinkFinder(String sourcePage) 
{
    try
    {
        this.url = new URL(sourcePage);
    }
    catch (MalformedURLException e)
    {
        System.out.print("Malformed URL Exception: Setting URL to NULL");
        this.url = null;
    }

}
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  1. Editorial Team
    Editorial Team
    2026-06-14T10:38:20+00:00Added an answer on June 14, 2026 at 10:38 am

    No you can’t. The only way your constructor will not return an object (or return null) is if it is not completed.

    If you want a null object if the URL is malformed, then the solution would be to apply a try block around your object instantiation code (i.e. new LinkFinder(url)), and in its catch block set the reference to null.

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