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Home/ Questions/Q 786815
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T21:06:14+00:00 2026-05-14T21:06:14+00:00

I have an object o which guaranteed at runtime to be one of three

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I have an object o which guaranteed at runtime to be one of three types A, B, or C, all of which implement a common interface I. I can control I, but not A, B, or C. (Thus I could use an empty marker interface, or somehow take advantage of the similarities in the types by using the interface, but I can’t add new methods or change existing ones in the types.)

I also have a series of methods MethodA, MethodB, and MethodC. The runtime type of o is looked up and is then used as a parameter to these methods.

public void MethodA(A a) { ... }
public void MethodB(B b) { ... }
public void MethodC(C c) { ... }

Using this strategy, right now a check has to be performed on the type of o to determine which method should be invoked. Instead, I would like to simply have three overloaded methods:

public void Method(A a) { ... } // these are all overloads of each other
public void Method(B b) { ... }
public void Method(C c) { ... }

Now I’m letting C# do the dispatch instead of doing it manually myself. Can this be done? The naive straightforward approach doesn’t work, of course:

Cannot resolve method ‘Method(object)’. Candidates are:

  • void Method(A)
  • void Method(B)
  • void Method(C)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T21:06:14+00:00Added an answer on May 14, 2026 at 9:06 pm

    How about something like this?

    private Dictionary<Type, Action<I>> _mapping = new Dictionary<Type, Action<I>>
    { 
      { typeof(A), i => MethodA(i as A)},
      { typeof(B), i => MethodB(i as B)},
      { typeof(C), i => MethodC(i as C)},
    };
    
    private void ExecuteBasedOnType(object value)
    {
        if(_mapping.ContainsKey(value.GetType()))
           _mapping(value.GetType())(value as I);
    }
    
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