Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 64065
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 10, 20262026-05-10T18:43:53+00:00 2026-05-10T18:43:53+00:00

I have an object, that is facing a particular direction with (for instance) a

  • 0

I have an object, that is facing a particular direction with (for instance) a 45 degree field of view, and a limit view range. I have done all the initial checks (Quadtree node, and distance), but now I need to check if a particular object is within that view cone, (In this case to decide only to follow that object if we can see it).

Apart from casting a ray for each degree from Direction - (FieldOfView / 2) to Direction + (FieldOfView / 2) (I am doing that at the moment and it is horrible), what is the best way to do this visibility check?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-10T18:43:53+00:00Added an answer on May 10, 2026 at 6:43 pm

    Compute the angle between your view direction (understood as a vector) and the vector that starts at you and ends at the object. If it falls under FieldOfView/2, you can view the object.

    That angle is:

    arccos(scalarProduct(viewDirection, (object - you)) / (norm(viewDirection)*norm(object - you))). 
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have an object that is mapped to a cookie as a serialized base-64
I have an object that implements IDisposable that is registered with the Windsor Container
I have an object that needs a test if the object data is valid.
I have an object that starts a thread, opens a file, and waits for
I have an object that implements ArrayAccess , Iterator and Countable . That produces
I have an object that can build itself from an XML string, and write
I have an object that has a list of abstract 'aninamls'. i.e. var animals
I have an object that is generated in one class public class CreatingClass {
I have an object that is mapped to have a set of objects, very
I have an object that I want to be able to stream. But I

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.