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Home/ Questions/Q 6879695
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:52:44+00:00 2026-05-27T04:52:44+00:00

I have an ordered dictionary ( OrderedDict ) sorted by value. How can I

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I have an ordered dictionary (OrderedDict) sorted by value. How can I get the top (say 25) key values and add them to a new dictionary?
For example: I have something like this:

dictionary={'a':10,'b':20,'c':30,'d':5}
ordered=OrderedDict(sorted(dictionary.items(), key=lambda x: x[1],reverse=True))

Now ordered is an ordered dictionary, I want to create a dictionary, say by taking the top 2 most-frequent items and their keys:

frequent={'c':30,'b':20}
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  1. Editorial Team
    Editorial Team
    2026-05-27T04:52:45+00:00Added an answer on May 27, 2026 at 4:52 am

    The primary purpose of collections.OrderedDict is retaining the order in which the elements were inserted.
    What you want here is collections.Counter, which has the n-most-frequent functionality built-in:

    >>> dictionary={'a':10,'b':20,'c':30,'d':5}
    >>> import collections
    >>> collections.Counter(dictionary).most_common(2)
    [('c', 30), ('b', 20)]
    
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