Question

I have an rss feed that is formatted something like this:

<item>
     <posturl>mysite.com/abc.html</posturl>
     <imagepath>123.jpg</imagepath>
</item>
<item>
     <posturl>mysite.com/def.html</posturl>
     <imagepath>456.jpg</imagepath>        
</item>
<item>
     <posturl>mysite.com/ghi.html</posturl>
     <imagepath>789.jpg</imagepath>    
</item>

I have a script where I want to extract both the values above. I can extract one of the values and build html code using code like:

<?php
     $xml = simplexml_load_file('http://myrssfeed.com');
     $imgs = $xml->xpath('//imagepath');
            echo '<ul>';
         foreach($imgs as $output1) {
            echo '<li><img src="' . $output1 . '" ></li>';
            }

            echo '</ul>';
 ?>

This works like a charm thanks to all the help from people here. But I need to expand that second echo line to read something like:

echo  '<li><a href="' . $output2 . '"><img src="' . $output1 . '" ></a></li>';

I need help on how to extract $output2 = posturl within the same item as $output1.

Basically I need to display the images as links… both imagepath and posturl are elements within item.

Many thanks.

Answer 1

You could select the <item> elements instead of <posturl> and <imagepath>. Like this:

$xml = simplexml_load_file('http://myrssfeed.com');

echo '<ul>';

foreach($xml->xpath('//item') as $item) { 
    printf('<li><a href="%s"><img src="%s" /></a></li>', 
        $item->posturl, $item->imagepath); 
}

echo '</ul>';