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Home/ Questions/Q 3790866
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T12:22:52+00:00 2026-05-19T12:22:52+00:00

I have an std::vector defined as: std::vector<glm::vec3> faces; And I want to use the

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I have an std::vector defined as:

std::vector<glm::vec3> faces;

And I want to use the size of that vector as the length of an array of floats. Right now I’m trying to do it like this:

float vertices[faces.size()][3];

But I keep getting errors saying that you must use a constant value. I thought maybe it was because the size of the vector can change, so I tried this instead:

const int size = faces.size();
float vertices[size][3];

But I still get the same error. Is it possible to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-19T12:22:52+00:00Added an answer on May 19, 2026 at 12:22 pm

    Why do you want to use a C array anyway? A vector would be much more apt here.

    vector<vector<float> > vertices(faces.size(), vector<float>(3));
    

    And if you already know the size of the inner vector and its size is fixed, it’s a safe bet that a struct would be better suited than a vector here:

    struct vertex {
        float x;
        float y;
        float z;
    };
    
    vector<vertex> vertices(faces.size());
    

    The usefulness of C-style vectors is severely limited in C++. The only use is basically if you know their size (and usually also the contents) at compile-time and use them as a glorified constant. For everything else, there exist better containers. And even this niche is filled in the next standard by std::array.

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