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Home/ Questions/Q 9016015
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T03:53:22+00:00 2026-06-16T03:53:22+00:00

I have an variable qsubFile=submitJob.sh echo $qsubFile returns submitJob.sh without the double quotes. Now,

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I have an variable

qsubFile="submitJob.sh"

echo $qsubFile returns submitJob.sh without the double quotes.

Now, I want to find the line containing the string qsubFile="someOtherFile.sh" and replace it to qsubFile="submitJob.sh" in the file "write.sh".

I tried using

sed -i '/qsubFile=/c\qsubFile="'"$qsubFile"'"' write.sh

qsubFile=""

I can’t seem to get the proper syntax for this.

but it replaces it as

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  1. Editorial Team
    Editorial Team
    2026-06-16T03:53:25+00:00Added an answer on June 16, 2026 at 3:53 am

    You just need single quotes for sed to do this, there is no problem with the double quotes inside the single quotes:

    sed -i 's/qsubFile="someOtherFile.sh"/qsubFile="submitJob.sh"/g' write.sh
    

    If "someOtherFile.sh" isn’t a fixed string in write.sh than use the follow to replace them all:

    $ sed  -i 's/qsubFile="[^"]*"/qsubFile="submitJob.sh"/g' write.sh
    

    Regex "[^"]*":

    "      # double quote
    [^"]*  # Anything not a double quote
    "      # double quote
    

    Seems I misread the question the first time the correct quoting is to use the variable $qsubFile is, you missed the last /:

    sed -i 's/qsubFile="[^"]*"/qsubFile="'"$qsubFile"'"/g' write.sh
    
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