Question

I have an XML document similar to:

<tag>
   <content>adsfasdf<b>asdf</b></content>
</tag>

I would like for the XSLT to select the content element and show all of the content:

<xsl:value-of select="/tag/content"/> 

The XSLT is configured to render as HTML. Is there a way that I can get the value-of/copy-of to display the exact content without having to render it?

What I’m looking for is

asdfasdf<b>asdf</b> 

And not:

asdfasdf asdf

Answer 1

You need to escape the tag names within the content, I’d recommend something like:

<xsl:template match="content//*">
    <xsl:value-of select="concat('&lt;',name(),'&gt;')"/>
    <xsl:apply-templates/>
    <xsl:value-of select="concat('&lt;/',name(),'&gt;')"/>
</xsl:template>

which you then can call with:

<xsl:apply-templates select="/tag/content"/>