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Home/ Questions/Q 74243
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Asked: May 10, 20262026-05-10T20:19:40+00:00 2026-05-10T20:19:40+00:00

I have an XML document something like ::: <?xml version=1.0 encoding=utf-8?> <?mso-application progid=Excel.Sheet?> <Workbook

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I have an XML document something like :::

<?xml version='1.0' encoding='utf-8'?> <?mso-application progid='Excel.Sheet'?> <Workbook xmlns:ss='urn:schemas-microsoft-com:office:spreadsheet'           xmlns:o='urn:schemas-microsoft-com:office:office'           xmlns:x='urn:schemas-microsoft-com:office:excel'           xmlns='urn:schemas-microsoft-com:office:spreadsheet'>   <Worksheet ss:Name='Worksheet1'>     <Table>       <Column ss:Width='100'></Column>        <Row>         <Cell ss:Index='1' ss:StyleID='headerStyle'>           <Data ss:Type='String'>Submitted By</Data>         </Cell>       </Row>       <Row>         <Cell ss:Index='1' ss:StyleID='alternatingItemStyle'>           <Data ss:Type='String'>Value1-0</Data>         </Cell>       </Row>     </Table>     <AutoFilter xmlns='urn:schemas-microsoft-com:office:excel'                 x:Range='R1C1:R1C5'></AutoFilter>   </Worksheet> </Workbook> 

The problem is when trying to select Rows with

  <xsl:for-each select='//Row'>     <xsl:copy-of select='.'/>   </xsl:for-each> 

It is not matching. I removed all of the name-spacing and it works fine. So, how do I get the ‘select’ to match Row?

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  1. 2026-05-10T20:19:40+00:00Added an answer on May 10, 2026 at 8:19 pm

    Declare a namespace prefix for the namespace in your XSLT and then select using that prefix:

    <xsl:stylesheet ... xmlns:os='urn:schemas-microsoft-com:office:spreadsheet'>   ...      <xsl:for-each select='//os:Row'>     ...   </xsl:for-each>   ... </xsl:stylesheet> 

    This usually results in XPaths that are easy to read. However, XSLT/XPath tools generate the following, equivalent code:

    <xsl:for-each select='//*[local-name()='Row' = and namespace-uri()='urn:schemas-microsoft-com:office:spreadsheet']'>    ... </xsl:for-each> 
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