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Home/ Questions/Q 4609456
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T00:59:21+00:00 2026-05-22T00:59:21+00:00

I have an XML file and the data is passed through parameters, like so:

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I have an XML file and the data is passed through parameters, like so:

<node id="a" title="Title A">
    <node id="b"  title="Title B">
       <node id="c"  title="Title C">
       </node>
    </node>
    <node id="d"  title="Title D">
    </node>
</node>

How can I loop recursively through this XML and print only the ID of every node in a list? i.e.

<ul>
   <li>a</li>
   <ul>
      <li>b</li>
      <ul>
         <li>c</li>
      </ul>
   </ul>
   <ul>
      <li>d</li>
   </ul>
</ul>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T00:59:22+00:00Added an answer on May 22, 2026 at 12:59 am

    Although it would be possible without xslt, I think this is more reusable:

    <?php
    $dom = new DOMDocument();
    $dom->loadXml('<node id="a" title="Title A">
        <node id="b"  title="Title B">
           <node id="c"  title="Title C">
           </node>
        </node>
        <node id="d"  title="Title D">
        </node>
    </node>');
    
    
    $xsl = new DOMDocument;
    $xsl->loadXml('<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
        <xsl:template match="/">
            <ul><xsl:apply-templates /></ul>
        </xsl:template>
    
        <xsl:template match="node">
            <li><xsl:value-of select="@title" /> (<xsl:value-of select="@id" />)
                <xsl:if test="count(descendant::node) > 0">
                    <ul><xsl:apply-templates /></ul>
                </xsl:if>
            </li>
        </xsl:template>
    </xsl:stylesheet>', LIBXML_NOCDATA);
    
    $xslt = new XSLTProcessor();
    $xslt->importStylesheet($xsl);
    
    echo $xslt->transformToXML($dom);
    
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