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Editorial Team
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Asked: 2026-05-13T22:38:16+00:00

I have an XML file full of bookmarks from Google Bookmarks. (File: http://gist.github.com/324844 )

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I have an XML file full of bookmarks from Google Bookmarks. (File: http://gist.github.com/324844) I want to pull the bookmark based on this path: xml_api_reply->bookmarks-bookmark->labels->label.

So, my question is How can I use SimpleXML to grab the bookmarks that have the label Inspiration? Some bookmarks may have more than one bookmark.

EDIT: The file listed above is just a sample.

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1 Answer

  1. Editorial Team

    You’ll have to use XPath for that.

    The nodes you want:

    /xml_api_reply/bookmarks/bookmark

    The filter you want to apply:

    [labels/label = "Inspiration"]

    Gives you the following XPath query:

    /xml_api_reply/bookmarks/bookmark[labels/label = "Inspiration"]

    Used in a script:

    $xml_api_reply = simplexml_load_file('http://gist.github.com/raw/324844/e4b1e05118b09c61c2a5b8b9a3bab92b895de07c/GoogleBookmarksXMLOutput');

foreach ($xml_api_reply->xpath('/xml_api_reply/bookmarks/bookmark[labels/label = "Inspiration"]') as $bookmark)
{
    // ...
    echo $bookmark->asXML();
}

    Alternatively, you could also use the shorter //bookmark[labels/label = "Inspiration"] — see that XPath tutorial

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