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Home/ Questions/Q 6640179
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T23:38:34+00:00 2026-05-25T23:38:34+00:00

I have an xml file inside the res folder under the xml forlder. I

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I have an xml file inside the res folder under the xml forlder. I want to parse it with SAX. I know there are lots of example but I want to understand InputStream, InputSource, File deeply. I can reach the file writing R.xml.hippo (hippo is the name of the xml file).

But how can I give this resource as a stream?
I know when I write R.xml.hippo to anywhere it will be reference(int) but I want give it as a source. What is and how converting an int to starting point of stream?

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  1. Editorial Team
    Editorial Team
    2026-05-25T23:38:34+00:00Added an answer on May 25, 2026 at 11:38 pm

    You should place the file inside the raw folder. Then you can access it via Resources.openRawResource(). For more information refer to Android Developer’s page.

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