Question

I have an XML file like below, and I want to convert it into a Java object.

<P1>
    <CTS>
        Hello
    </CTS>
    <CTS>
        World
    </CTS>
<P1>    

So I created the following Java classes with their properties.

P1 class

@XmlRootElement
public class P1 {
    @XmlElement(name = "CTS")
    List<CTS> cts;
}

CTS class

public class CTS {
    String ct;
}

Test Class

File file = new File("D:\\ContentTemp.xml");
            JAXBContext jaxbContext = JAXBContext.newInstance(P1.class);
     
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            P1 p = (P1) jaxbUnmarshaller.unmarshal(file);

But I am getting the following error:

com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException:
2 counts of IllegalAnnotationExceptions
Class has two properties of the same name "cts"

Answer 1

com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException:
2 counts of IllegalAnnotationExceptions
Class has two properties of the same name "cts"

By default a JAXB (JSR-222) implementation creates mappings based on properties and annotated fields. When you annotate a field for which there is also a property it will cause this error.

You have two options:

1. Use @XmlAccessorType(XmlAccessType.FIELD)

   You could annotate the field you need to specify @XmlAccessorType(XmlAccessType.FIELD) on the class.

   @XmlRootElement(name="P1)
   @XmlAccessorType(XmlAccessType.FIELD)
   public class P1 {
   
       @XmlElement(name = "CTS")
       List<CTS> cts;
   
   }
   

2. Option #2 – Annotate the Property (get method)**

   Alternatively you could annotate the get method.

   @XmlRootElement(name="P1)
   public class P1 {
   
       List<CTS> cts;
   
       @XmlElement(name = "CTS")
       public List<CTS> getCts() {
           return cts;
       }
   
   }
   

For More Information

• http://blog.bdoughan.com/2011/06/using-jaxbs-xmlaccessortype-to.html

---

FULL EXAMPLE

CTS

You can use the @XmlValue annotation to map to Java class to a complex type with simple content.

@XmlAccessorType(XmlAccessType.FIELD)
public class CTS {

    @XmlValue
    String ct;

}

P1

import java.util.List;
import javax.xml.bind.annotation.*;

@XmlRootElement(name="P1")
@XmlAccessorType(XmlAccessType.FIELD)
public class P1 {

    @XmlElement(name = "CTS")
    List<CTS> cts;

}

Demo

import java.io.File;
import javax.xml.bind.*;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(P1.class);
        
        Unmarshaller unmarshaller = jc.createUnmarshaller();
        File xml = new File("src/forum13987708/input.xml");
        P1 p1 = (P1) unmarshaller.unmarshal(xml);
        
        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(p1, System.out);
    }
    
}

input.xml/Output

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<P1>
    <CTS>
        Hello
    </CTS>
    <CTS>
        World
    </CTS>
</P1>

For More Information

• http://blog.bdoughan.com/2011/06/jaxb-and-complex-types-with-simple.html