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Home/ Questions/Q 497623
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:47:57+00:00 2026-05-13T05:47:57+00:00

I have an XML file that I want to transform using an XSLT. It

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I have an XML file that I want to transform using an XSLT. It only works when I remove all the attributes from the following part of the XML file:

<DiscoveryClientData 
  xmlns="http://www.frontrange.com/centennial/discovery" 
  SchemaVersion="0.6" 
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
  xsi:schemaLocation="http://www.frontrange.com/centennial/discovery DiscoveryClientData-0.6.xsd"
/>

The XSLT starts off like this:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
      <xsl:template match="DiscoveryClientData">

Does anyone have any idea why this might be failing? The failure is that it doesn’t place any element tags around the transformed data, it just spits it all out in one continuous string.

Thanks!

Edit: Ok, the example given below works, but is there a way I can define the prefix only once in the XSLT file? So I don’t have to re-write my whole XSLT file? Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:47:58+00:00Added an answer on May 13, 2026 at 5:47 am

    Your XML is not in the default namespace, so your XSLT does not find any nodes to process.

    Check Here for how to assign a namespace to the XSL template.

    Adding this by popular demand. Taken from: Here

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
       xmlns:b="urn:xmlns:25hoursaday-com:bookstore">
    
    <xsl:template match="b:bookstore">
    <book-titles>
    <xsl:apply-templates select="b:book/b:title"/>
    </book-titles>
    </xsl:template>
    
    <xsl:template match="b:title"> 
    <xsl:copy-of select="." />
    </xsl:template>
    </xsl:stylesheet>
    
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