Question

I have an XML from customer where I cannot be certain of the namespace. I need to replace value of some attribute. Here is the input XML example:

<?xml version="1.0" encoding="UTF-8"?>
<NetworkSection xmlns:ovf="http://com/deployment/1.0">
    <Network ovf:name="bridged"/>
</NetworkSection>

I want to receive the XML like this:

<?xml version="1.0" encoding="UTF-8"?>
<NetworkSection xmlns:ovf="http://com/deployment/1.0">
    <Network ovf:name="VM network"/>
</NetworkSection>

Here the XSL I try to use:

<?xml version="1.0" encoding="utf-8"?>
  <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" encoding="utf-8"/>
  <xsl:template match="NetworkSection/Network/@*[local-name()='name']">
    <xsl:attribute name='name'>VM Network</xsl:attribute>
  </xsl:template>

  <xsl:template match="@*|node()"> 
    <xsl:copy> 
      <xsl:apply-templates select="@*|node()"/> 
    </xsl:copy> 
  </xsl:template>
</xsl:stylesheet> 

The problem is that I lose the attribute namespace.
I cannot define namespace in my XSL, because it may vary in different input XMLs, I just want to change the attribute value.

Is it possible to do such replacing without specifying namespace in XSL?
Thanks in advance.

Answer 1

This can be achieved by use of the name() and namespace-uri() functions.

<xsl:attribute name="{name()}" namespace="{namespace-uri()}">VM Network</xsl:attribute>

When you use this line in your XSLT, you should get the output you desire

<Network ovf:name="VM network"/>