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Home/ Questions/Q 3807430
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T14:59:24+00:00 2026-05-19T14:59:24+00:00

I have an XML in this format <tests> <test> <testid>1</testid> <testval>8</testval> <testname> <testid>1</testid> <testname>test

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I have an XML in this format

<tests>
    <test>
        <testid>1</testid>
        <testval>8</testval>
        <testname>
            <testid>1</testid>
            <testname>test 1</testname>
        </testname>
    </test>
    <test>
        <testid>2</testid>
        <testval>5</testval>
        <testname>
            <testid>2</testid>
            <testname>test 2</testname>
        </testname>
    </test>
</tests>

using TSQL/XML query how do I achieve this result

[Testid][TestVal][TestName]
    1       8      Test 1
    2       5      Test 2
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T14:59:25+00:00Added an answer on May 19, 2026 at 2:59 pm

    Try this:

    declare @input XML = '<tests>
        <test>
            <testid>1</testid>
            <testval>8</testval>
            <testname>
                <testid>1</testid>
                <testname>test 1</testname>
            </testname>
        </test>
        <test>
            <testid>2</testid>
            <testval>5</testval>
            <testname>
                <testid>2</testid>
                <testname>test 2</testname>
            </testname>
        </test>
    </tests>'
    
    select
        Tests.value('(testid)[1]', 'int') as 'TestID',
        Tests.value('(testval)[1]', 'int') as 'TestVal',
        Tests.value('(testname/testname)[1]', 'varchar(20)') as 'TestName'
    FROM 
        @input.nodes('/tests/test') as List(Tests)
    

    This gives you the desired output.

    If you have a table of those XML columns, you might need to use a slightly different approach (using CROSS APPLY):

    select
        tbl.SomeValue, tbl.SomeOtherValue,
        Tests.value('(testid)[1]', 'int') as 'TestID',
        Tests.value('(testval)[1]', 'int') as 'TestVal',
        Tests.value('(testname/testname)[1]', 'varchar(20)') as 'TestName'
    FROM 
        dbo.YourTable tbl
    CROSS APPLY
        tbl.XmlColumn.nodes('/tests/test') as List(Tests)
    
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