Question

i have an XML like

var test:XML = new XML( <record id="5" name="AccountTransactions"
    <field id="34" type="Nuber"/>
    </record>);

i want to remove all the attributes other than id and type in all nodes of XML. by this code i am unable to do this. can you suggest better solution, other than loops.

var atts:XMLListCollection = new XMLListCollection(test.descendants().attributes().((localName() != "id") && (localName() != "type")));
atts.removeAll(); trace(test)

it still show all attributes :/

Answer 1

    var test:XML = new XML( '<record id="5" name="AccountTransactions"><field id="34" type="Nuber" score="ded"/><field id="35" type="Nuber" score="sc"/></record>');
    var attributes:XMLList = test.field.@*;
    var length:int = attributes.length();
    for (var i:int = 0; i < length; i++) {
        (attributes[i].localName() != "id" && attributes[i].localName() != "type") ? [delete attributes[i], length--] : void;
    }
    trace(test);