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Asked: 2026-05-22T23:57:38+00:00

I have an XML <p id=section02_01/> <p id=section02_02/> <p id=section02_03/> <p id=section02_04/> <p id=section02_05/>

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I have an XML 

 <p id="section02_01"/>
 <p id="section02_02"/>
 <p id="section02_03"/>
 <p id="section02_04"/>
 <p id="section02_05"/>
 <p id="section02_06"/>
 <p id="section02_07"/>
     <p id="section02_08"/>

I have the value of id as section02_05. How can I find the position of corresponding p node using XML or E4X. Assume that the root node for this.

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1 Answer

  1. Editorial Team

    If have understand your question, you can use the method childIndex

    var xml:XML=<xml>
<p id="section02_01"/>
 <p id="section02_02"/>
 <p id="section02_03"/>
 <p id="section02_04"/>
 <p id="section02_05"/>
 <p id="section02_06"/>
 <p id="section02_07"/>
 <p id="section02_08"/>
</xml>

trace(xml.p.(@id=="section02_05").childIndex())
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