Question

I have an xml

 <Root>
  <Parent>
    <Child1><Node1>AAA</Node1><Node2>BBB</Node2></Child1>
    <Child2><NodeX>XXX</NodeX><NodeY>YYY</NodeY></Child2>
    <Child1><Node1>EEE</Node1><Node2>FFF</Node2></Child1>
    <Child2><NodeX>GGG</NodeX><NodeY>HHH</NodeY></Child2>
    <OtherChild></OtherChild>

  </Parent>
</Root>

Child2 always will be with child1. I need to know how I can loop through using xsl:foreach and create an XML output example. I may have other nodes like <OtherChild> but my concern
is only Child1 and Chid2 nodes

    <TransformedXML>
  <Child attributefromNode1="AAA" attributefromNode2="BBB" attributefromNodeX="XXX" attributeFromNodeY="YYY"/>
  <Child attributefromnode1="EEE" attributefromNode2="FFF" attributefromNodeX="GGG" attributeFromNodeY="HHH"/>
</TransformedXML>

My question is how do I loop in XSLT considering Child2 node will follow a Child1 always?

Answer 1

I this something like this should do the trick:

  <xsl:stylesheet version="1.0"                 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns="http://www.w3.org/TR/xhtml1/strict">
  <xsl:output
   method="xml"
   indent="yes" />

  <xsl:template match="/">
<xsl:for-each select="Root/Parent/Child1">
<Child>
  <xsl:attribute name="attributefromNode1">
    <xsl:value-of select="Node1" />

  </xsl:attribute>
  <xsl:attribute name="attributefromNode2" >
    <xsl:value-of select="Node2" />

  </xsl:attribute>
  <xsl:attribute name="attributefromNodeX">
    <xsl:value-of select="following-sibling::Child2/NodeX" />

  </xsl:attribute>
  <xsl:attribute name="attributefromNodeY">
    <xsl:value-of select="following-sibling::Child2/NodeY" />

  </xsl:attribute>



</Child>   
    </xsl:for-each>
    </xsl:template>
</xsl:stylesheet>