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Home/ Questions/Q 7592633
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T20:57:27+00:00 2026-05-30T20:57:27+00:00

I have an XML structure like this: mytree = <path> <to> <nodes> <info>1</info> <info>2</info>

  • 0

I have an XML structure like this:

mytree = """
<path>
    <to>
        <nodes>
            <info>1</info>
            <info>2</info>
            <info>3</info>
        </nodes>
    </to>
</path>
"""

I’m currently using xpath in python lxml to grab the nodes:

>>> from lxml import etree   
>>> info = etree.XML(mytree)   
>>> print info.xpath("/path/to/nodes/info")
[<Element info at 0x15af620>, <Element info at 0x15af940>, <Element info at 0x15af850>]  
>>> for x in info.xpath("/path/to/nodes/info"):
            print x.text

1
2
3

This is great, but is there a cleaner way to grab just the internal texts as a list, rather than having to write the for-loop afterwards?
Something like:

print info.xpath("/path/to/nodes/info/text")

(but that doesn’t work)

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  1. Editorial Team
    Editorial Team
    2026-05-30T20:57:29+00:00Added an answer on May 30, 2026 at 8:57 pm

    You can use:

    print info.xpath("/path/to/nodes/info/text()")
    
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