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Home/ Questions/Q 6956809
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:55:04+00:00 2026-05-27T14:55:04+00:00

I have an XML with differently namespaced attributes – it’s basicly a kind of

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I have an XML with differently namespaced attributes – it’s basicly a kind of extended XHTML. I want to dump all the non-xhtml namespaced attributes.

Examplary source XML:

<html>
  <body>
    <p class="test" xy:foo="true">blah</p>
  </body>
</html>

At the moment, i have the following XSLT template:

<xsl:template match="@*">
    <xsl:choose>
        <xsl:when test='namespace-uri()="http://www.w3.org/1999/xhtml"'><xsl:copy-of select="."/></xsl:when>
        <xsl:otherwise></xsl:otherwise>
    </xsl:choose>
</xsl:template>

Desired output XML:

<html>
  <body>
    <p class="test">blah</p>
  </body>
</html>

But it doesn’t seem to match, because i get an output XML completely without attributes. I have the feeling that namespace-uri() does not work as expected. Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:55:05+00:00Added an answer on May 27, 2026 at 2:55 pm

    The attributes on XHTML elements (like your class one) are attributes in no namespace, not in the XHTML namespace. So use

    <xsl:template match="@*[namespace-uri() != '']"/>
    

    plus the identity transformation template.

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