Question

I have an XQuery as under

DECLARE @x XML
SELECT @x = '<PartnerEmails>
<Email>[e-mail]</Email>
<Email>[e-mail]</Email>
</PartnerEmails>'
SELECT @x.query('data(PartnerEmails/Email)').value('.','varchar(100)') AS Val

Actual Output:

Val
[e-mail] [e-mail]

Expected Output

[e-mail]
[e-mail]

i.e. In two different rows.

How to do so?

Answer 1

Use this:

SELECT 
    node.value('.','varchar(100)') AS Val
FROM
    @x.nodes('/PartnerEmails/Email') AS PE(Node)    

Since you have multiple nodes inside <PartnerEmails>, you need to use the .nodes() function to create an “inline” table of XML fragments – each “row” in that table contains one <Email> node which you can then query on (and extract the contents of the XML node).