Question

I have Array:

$arr = array();
$arr[0] = array(2628927 => "8250843");
$arr[1] = array(2628927 => "8250843");
$arr[2] = array(2783907 => "8250843");
$arr[3] = array(2783907 => "8250843");
$arr[4] = array(2648250 => "8250843");
$arr[5] = array(2628927 => "8250843");

$arr1 = array();

unique ligament key=> value i get with script

foreach($arr as $a)
{
    if(!in_array($a, $arr1)){
        $arr1[] = $a;
    }
}

than i output value unique ligament key=> value:

foreach ($arr1 as $keys => $elms ) {
foreach ( $elms as $key => $val ) {
echo "$key = $val<br>";

How to count how many identical ligament $ key = $ val in the general array $arr?

}
}

For example count for 2628927 => “8250843” will be 3

How get this?

IF YOU WANT VOTE DOWN PLEASE GIVE ANSWER.

BIG THANKS)

Answer 1

If your expected result is 3, then try the below:

$count = count(array_unique(array_map('serialize', $arr)));

Edit:

function foo($arr, $target) {
  $data = array_count_values(array_map('serialize', $arr));
  $key = serialize($target);
  return isset($data[$key]) ? $data[$key] : 0;
}

$arr = array();
$arr[0] = array(2628927 => "8250843");
$arr[1] = array(2628927 => "8250843");
$arr[2] = array(2783907 => "8250843");
$arr[3] = array(2783907 => "8250843");
$arr[4] = array(2648250 => "8250843");
$arr[5] = array(2628927 => "8250843");

echo foo($arr, array(2628927 => "8250843")); // the result is 3