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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T00:17:01+00:00 2026-05-25T00:17:01+00:00

I have been playing about with a GUI today and trying add different elements

  • 0

I have been playing about with a GUI today and trying add different elements to it,

public void actionPerformed(ActionEvent e)
    {
        if (e.getSource() == jButton1)                              
        {
            //Do Something
        }

        JComboBox cb = (JComboBox)e.getSource();
        String petName = (String)cb.getSelectedItem();

        if(petName == "Cat")
        {
            //Do Something
        }

   }

When i click jButton1 it does what i want it to do and when i select “Cat” from the combobox it does what i want it to do, but only when i click jButton1 and not when i select cat it gives me the following error

javax.swing.JButton cannot be cast to javax.swing.JComboBox

Any ideas obviously something to do with the comboxbox code and when i remove the code from JCombobox down the error doesnt appear.

Any help would be good, not homework just be messing about and seeing if i can learn new things

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T00:17:01+00:00Added an answer on May 25, 2026 at 12:17 am

    First of all, don’t compare strings using ==, use the equals method. That is, change

    petName == "Cat"
    

    to

    petName.equals("Cat")
    

    (== compares references, not the objects the references refer to)

    Related question:

    • How do I compare strings in Java?

    Regarding the “JButton cannot be cast to JComboBox”-issue, it seems to me like you’re simply forgetting an else there. Try the following:

    if (e.getSource() == jButton1) {
        //Do Something
    } else {
    
        JComboBox cb = (JComboBox)e.getSource();
        String petName = (String)cb.getSelectedItem();
    
        if(petName == "Cat") {
            //Do Something
        }
    }
    

    (or simply return from the method once you’re done with the Do something related to the JButton.)

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