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Home/ Questions/Q 5974151
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Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T20:54:09+00:00 2026-05-22T20:54:09+00:00

I have been playing around with this and wanted to get a second opinion.

  • 0

I have been playing around with this and wanted to get a second opinion.

Here is the problem –

I want to order these results by who the person reports to (i.e. there boss)

--- 
- !ruby/object:History 
 attributes: 
  id: 1392
  job_title: Global Leader
  reports_to:
  attributes_cache: {}

- !ruby/object:History 
 attributes: 
  id: 1393
  job_title: Programme Organiser
  reports_to: 1392
  attributes_cache: {}

- !ruby/object:History 
 attributes: 
  id: 1394
  job_title: Programme Lead
  reports_to: 1393
  attributes_cache: {}

they will be outputted in json so will look like this

{id: 1394, some_attributes, children: {id: 1393, some_attributes, children: { etc }}

I wrote this function but it started to look really bad

 candidates.each do |candidate, index|
  if !candidate.reports_to.present?
    structure << candidate
    candidates.to_a.delete_if {|candidate_inst| candidate_inst == candidate}
    candidates.each do |child|
      if child.reports_to == candidate.candidate_id
        # add child to children of parent
      end
    end
 end

There must be a cleaner way of doing this ??

Thanks, Alex

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T20:54:10+00:00Added an answer on May 22, 2026 at 8:54 pm

    maybe you can achieve same goal using Enumerable#group_by, see docs

    candidates.group_by(&:reports_to)
    
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