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Home/ Questions/Q 7610189
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T01:21:34+00:00 2026-05-31T01:21:34+00:00

I have been reading here and there about multiple JQuery selectors but I couldn’t

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I have been reading here and there about multiple JQuery selectors but I couldn’t get the answer I was looking for.

$.fn.extend({
    sayHi:function() {
        console.log($(this).attr('class') + ' says hi');
    }
}
$('.class1,.class2').sayHi();

The last selector always calls the outermost item among the listed ones. Here’s what happens:

<div class="class1"><!-- only this one gets selected -->
    <div class="class2"></div>
</div>

What is the most elegant way to make it select all the indicated selectors no matter whether they’re wrapped by any other selector(s) indicated?

EDIT:

I know I can use it like

$('.class1').sayHi();
$('.class2').sayHi();

but I’m willing to bind it into a single call (I’m actually using more than 2 selectors).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T01:21:36+00:00Added an answer on May 31, 2026 at 1:21 am

    Is this what you are trying to do?

    (function ($) {
        $.fn.sayHi = function() {
            return this.each(function() {
                console.log($(this).attr('class') + ' says hi');
            });
        };
    })(jQuery);
    
    $('.class1, .class2').sayHi();
    
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