Question

I have been searching how to put more than one function in onchange and I found how something like this for example: onchange = "function1(); function2();".
My problem here is I have followed what does the example like, but only function1 is working, function2 is not working. If I make it otherwise to onchange = "function2(); function1();", only function2 is working, function1 is not working, the same.

Any ideas guys?
Thanks.

The functions, I used Ajax:

function1(test)
{
    var kode = test.value;
    if (!kode) return;
    xmlhttp.open('get', '../template/get_name-opr.php?kode='+kode, true);
    xmlhttp.onreadystatechange = function() {
        if ((xmlhttp.readyState == 4) && (xmlhttp.status == 200))
        {
            //alert(kode);
             document.getElementById("code").innerHTML = xmlhttp.responseText;
        }
        return false;
    }
    xmlhttp.send(null);
}

function2(test)
{
    var kode = test.value;
    if (!kode) return;
    xmlhttp**1**.open('get', '../template/get_name2-opr.php?kode='+kode, true);
    xmlhttp**1**.onreadystatechange = function() {
        if ((xmlhttp**1**.readyState == 4) && (xmlhttp**1**.status == 200))
        {
            //alert(kode);
             document.getElementById("code2").innerHTML = xmlhttp**1**.responseText;
        }
        return false;
    }
    xmlhttp**1**.send(null);
}

To solve my problem, I created two xmlhttp different. (xmlhttp and xmlhttp1).

Answer 1

Go through the link I gave, it seems to be problem with the way you are managing the xmlhttprequest objects, manage their instances properly, in your case because you are using the same xmlhttprequest for two simultaneous AJAX requests, only one of them is getting served. Either wait for one of them to get served or create two instances of the xmlhttprequest.

The statement xmlhttp.readystate = function() {...} obviously replaces the readystate property of that xmlhttprequest object, so on your second function, that is being replaced( because you are using the xmlhttprequest for both of them ). This is why you are seeing the funny behaviour.