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Home/ Questions/Q 546641
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:53:19+00:00 2026-05-13T10:53:19+00:00

I have been trying some fundamentals in javascript and here is what I observed.

  • 0

I have been trying some fundamentals in javascript and here is what I observed.

I wrote a prototype modification method for Function object

Function.prototype.method = function(name, func)
{
   this.prototype[name] = func;
   return this;
}

function pirates(value)
{
   console.log("I just throw away the value!!" + value);
}

pirates.method("my_skill", function(){
   console.log("Pirate skills");
});

new_pirate = new pirates(1234);

//SUCCESS
new_pirate.my_skill(); //prints "Pirate skills"

var someCrappyVariable = function(){
  return function()
  {
     console.log("I am going to just sit and do nothing. Really!");
  }
}();

**//Throws error. WHY???????? This was assigned a function, so ideally prototype should work on this too? Shouldn't it?**
someCrappyVariable.method("crappyFunction", function(){
   console.log("am I doomed?");
});

Why does last assignment throws an error that someCrappyVariable is not a function, when it was assigned a function reference earlier? I am confused.

Cheers

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:53:19+00:00Added an answer on May 13, 2026 at 10:53 am

    Your code should be throwing an error here:

    new_pirate.method("my_skill", function(){
       console.log("Pirate skills");
    });
    // TypeError: new_pirate.method is not a function
    

    … since method is not a direct or inherited method. The object created from new pirates(1234) will not inherit from Function; it will inherit from Object (which, ideally, shouldn’t be extended with custom methods).

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