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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T12:08:45+00:00 2026-06-14T12:08:45+00:00

I have been trying these code but there is something wrong. I simply want

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I have been trying these code but there is something wrong. I simply want to know if the first string is alphabetical.

def alp(s1):
    s2=sorted(s1)
    if s2 is s1:
        return True
    else:
        return False

This always prints False and when i say print s1 or s2, it says “NameError: name ‘s1’ is not defined”

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  1. Editorial Team
    Editorial Team
    2026-06-14T12:08:45+00:00Added an answer on June 14, 2026 at 12:08 pm

    is is identity testing which compares the object IDs, == is the equality testing:

    In [1]: s1 = "Hello World"
    In [2]: s2 = "Hello World"
    
    In [3]: s1 == s2
    Out[3]: True
    
    In [4]: s1 is s2
    Out[4]: False
    

    Also note that sorted returns a list, so change it to:

    if ''.join(s2) == s1:
    

    Or

    if ''.join(sorted(s2)) == s1:
    
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