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Home/ Questions/Q 1021259
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T11:17:05+00:00 2026-05-16T11:17:05+00:00

I have been trying to implement XOR linked list and its operations but I

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I have been trying to implement XOR linked list and its operations but I have not been able to do it properly.

Is it possible to implement it in C since XOR link list involves operations on addresses?

I would be very thankful if some actual working code is given.

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  1. Editorial Team
    Editorial Team
    2026-05-16T11:17:05+00:00Added an answer on May 16, 2026 at 11:17 am

    That’s an interesting idea that I have not seen before. With today’s fairly abundant memory, it seems like a lot of complexity for little gain (although not all platforms are flush with memory). Edit While doing my real work, my mind kept drifting back to it, so I added the function to create the new node and put it on the given end. Prettier now. It’s rather cool that both the addnode and traverse functions are symmetrical. Neither needs to know the direction. Just give it one end of the list and they operate correctly.

    And based on Darron’s comment (thanks), I changed the int to intptr_t for portability.

    #include <stdio.h>
    #include <malloc.h>
    #include <stdint.h>  // gcc needs this for intptr_t.  
    
    typedef struct xorll {
       int  value;
       struct xorll  *np;
    }  xorll;
    
    
    // traverse the list given either the head or the tail
    void traverse( xorll *start )  // point to head or tail
    {
       xorll *prev, *cur;
    
       cur = prev = start;
       while ( cur )
          {
          printf( "value = %d\n", cur->value );
          if ( cur->np == cur )
             // done
             break;
          if ( cur == prev )
             cur = cur->np;   // start of list
          else {
             xorll *save = cur;
             cur = (xorll*)((uintptr_t)prev ^ (uintptr_t)cur->np);
             prev = save;
             }
          }
    }
    
    // create a new node adding it to the given end and return it
    xorll* newnode( xorll *prev, xorll *cur, int value )
    {
       xorll *next;
    
       next = (xorll*)malloc( sizeof( xorll ));
       next->value = value;
       next->np = cur;  // end node points to previous one
    
       if ( cur == NULL )
          ; // very first node - we'll just return it
       else if ( prev == NULL ) {
          // this is the second node (they point at each other)
          cur->np = next;
          next->np = cur;
          }
       else {
          // do the xor magic
          cur->np = (xorll*)((uintptr_t)prev ^ (uintptr_t)next);
          }
    
       return next;
    }
    
    
    
    int main( int argc, char* argv[] )
    {
       xorll *head, *tail;
       int   value = 1;
    
       // the first two nodes point at each other.  Weird param calls to
       // get the list started
       head = tail = newnode( NULL, NULL, value++ );
       tail = newnode( NULL, tail, value++ );
    
       // now add a couple to the end
       tail = newnode( tail->np, tail, value++ );
       tail = newnode( tail->np, tail, value++ );
    
       // this is cool - add a new head node
       head = newnode( head->np, head, 999 );
    
    
       printf( "Forwards:\n" );
       traverse( head );
       printf( "Backwards:\n" );
       traverse( tail );
    
    
    }
    
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