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Home/ Questions/Q 910739
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T17:05:25+00:00 2026-05-15T17:05:25+00:00

I have been trying to port few linux drivers and realized that there is

  • 0

I have been trying to port few linux drivers and realized that there is substantial difference between kernel version 2.4 and 2.6 of linux.

In the 2.4 version of kernel, the module programming was as below –

#define MODULE
#include <linux/module.h>
#include <linux/kernel.h>

int init_module(void)      
{ 
printk(KERN_INFO "Hi \n"); 
return 0; 
}

void cleanup_module(void)  
{ 
printk(KERN_INFO "Bye \n"); 
}

But, with the 2.6 version of kernel, the following has to be done for modules –

#include <linux/init.h>
#include <linux/module.h>
#include <linux/kernel.h>

static int hi_init(void)
{
    printk(KERN_ALERT "Hi \n");
    return 0;
}

static void hi_exit(void)
{
    printk(KERN_ALERT "Bye \n");
}

module_init(hi_init);
module_exit(hi_exit);

What is the advantage of such changes in Kernel 2.6 and Why was that change required in kernel 2.6 of linux ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T17:05:25+00:00Added an answer on May 15, 2026 at 5:05 pm

    If you look at the definition of the new functions:

    /* Each module must use one module_init(). */
    #define module_init(initfn)                 \
    static inline initcall_t __inittest(void)       \
    { return initfn; }                  \
    int init_module(void) __attribute__((alias(#initfn)));
    
    /* This is only required if you want to be unloadable. */
    #define module_exit(exitfn)                 \
    static inline exitcall_t __exittest(void)       \
    { return exitfn; }                  \
    void cleanup_module(void) __attribute__((alias(#exitfn)));
    

    You’ll see it ensures that the right boilerplate is included so these special functions can be correctly treated by the compiler. It’s what the internal API of Linux does, it evolves if there are better ways of solving the problem.

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