Question

I have been trying to stop the exceptions but I cannot figure out how.
I tried parseInt, java.util.NormalExceptionMismatch etc.

Does anyone have any insight how to fix this problem? Formatting is a bit off due to copy and paste.

do
{
   System.out.print(
           "How many integers shall we compare? (Enter a positive integer):");
   select = intFind.nextInt();
   if (!intFind.hasNextInt()) 
       intFind.next();
       {
           // Display the following text in the event of an invalid input
           System.out.println("Invalid input!");
       }
}while(select < 0)

Other methods I have tried :

 do
    {
       System.out.print(
                   "How many integers shall we compare? (Enter a positive integer):");
       select = intFind.nextInt();
       {
            try{
                   select = intFind.nextInt();
               }catch (java.util.InputMismatchException e)
            {
               // Display the following text in the event of an invalid input
               System.out.println("Invalid input!");
               return;
            }
       }
    }while(select < 0)

Answer 1

It seems to me that you want to skip everything until you get an integer. This code here skips any input except an integer.

As long as there is no integer available (while (!in.hasNextInt())) discard the available input (in.next). When integer is available – read it (int num = in.nextInt();)

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (!in.hasNextInt()) {
            in.next();
        }
        int num = in.nextInt();
        System.out.println("Thank you for choosing " + num + " today.");
    }
}