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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:34:45+00:00 2026-05-27T03:34:45+00:00

I have been up far too long tonight working on a long program. But

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I have been up far too long tonight working on a long program. But I have hit a simple roadblock. Can any one tell me why this code is working the way it is?

I have two lists. I want list2 to only contain numbers that are not in list1.
logically this seems like it should work. But it doest at all. Why?

list1 = [1,2,3,4,5,6,7,8]
list2 = [12,15,16,7,34,23,5,23,76,89,9,45,4]


for ch in list2:
    if ch in list1:
         list2.remove(ch)

return list2

somehow, this returns:
[15, 7, 5, 23, 76, 9, 4]

Why?

and how can I accomplish what I need?

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:34:45+00:00Added an answer on May 27, 2026 at 3:34 am

    When you modify a sequence you are iterating over, it will yield unexpected results. I’d do it this way, which takes advantage of fast set operations.

    list2 = list(set(list2) - set(list1))
    

    Whether this is faster or slower than using a list comprehension depends on the sizes of list1 and list2, and whether you can make one into a set as part of initialization rather than multiple times in a loop.

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