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Asked: 2026-05-11T20:10:41+00:00

I have been using the clone keyword to duplicate objects like so: $x =

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I have been using the clone keyword to duplicate objects like so:

$x = clone $obj;

as per the manual.

This works fine when accessed by browser. phpinfo() reports PHP version 5.2.6.

However when run by cron or from the CLI I get

“Parse error: syntax error, unexpected T_VARIABLE”

from the clone keyword.

php -v reports PHP 4.4.9 (cli)

Is this error from a version conflict?

If I use clone() in my scripts like so:

$_SESSION['user'] = clone($userObject);

I get odd intermittent problems with the $_SESSION['user'] which do not occur when using the clone keyword.

Does this make any sense to anyone?

Any advice?

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1 Answer

  1. Editorial Team

    Turns out the server has 4 and 5 installed and the CLI reports 4.4.9 simply due to PATH order:

    From support:

    “Running the “php -v” command in the shell will always return V4. That’s because we have two separate installs for PHP on your server. One for V4 and one for V5, and the PHP 4 interpreter shows up in your PATH environment variable first. If you’d like to use V5 through the shell you’ll need to be sure to use the full path”

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