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Home/ Questions/Q 615839
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:15:46+00:00 2026-05-13T18:15:46+00:00

I have been using the jquery form plugin to submi forms on my page

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I have been using the jquery form plugin to submi forms on my page and it works great.

But when I try to submit a form that has been loaded using .load it doesn’t work.

This is my code:

$(document).ready(function() {                 
  //shows loading screen whilst posting via ajax
  $().ajaxStart($.blockUI).ajaxStop($.unblockUI);

  //post form add_customer ajax
  var options = { 
    target: '#alert',   
  };
  $.ajaxSettings.cache = false;
  $('#add_customer').submit(function() {
    $(this).ajaxSubmit(options);
    return false;
  }); 

  $('#theform').hide().load('form.php', function() {
    $(this).fadeIn();
    return false;
  });
});

What am I missing? can’t find a solution anywhere.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:15:47+00:00Added an answer on May 13, 2026 at 6:15 pm

    If you have a javascript code in file form.php and fetch it using $.load(), then all the js code will be stripped and you will only get the HTML part.

    Use $.get to load the whole page, including the js code.

    $.get('form.php',
          {},
          function(data){
            $('#theform').html(data).fadeIn();
          });
    

    Now all js code in form.php will running after it’s loaded and added to #theform area.

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