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Home/ Questions/Q 9154051
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T12:22:10+00:00 2026-06-17T12:22:10+00:00

I have been working on this project for quite a while and still I

  • 0

I have been working on this project for quite a while and still I am stuck on this code. Here’s the page where I can show the product list:

@mysql_connect("localhost", "root", "") or die();
@mysql_select_db("product") or die();

$result=mysql_query("select * from product_list ORDER BY name ASC");
while($row=mysql_fetch_array($result)){
  a href="show.php?code=$row['serial']|$row['name']
  $row['description']

show.php is:

//connect to server and select database; you may need it
@mysql_connect("localhost", "root", "") or die();
@mysql_select_db("bibendum") or die();

$serial = intval($_GET['serial']);
$query = "SELECT serial, name, desription FROM product_list WHERE serial = {$serial}"; 

echo "{$row[name]}";

I get this error:

Notice: Undefined index: serial in show.php on line 7
Notice: Undefined index: serial in show.php on line 8
Notice: Use of undefined constant name – assumed ‘name’ in show.php on line 10
Notice: Undefined variable: row in show.php on line 10

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  1. Editorial Team
    Editorial Team
    2026-06-17T12:22:11+00:00Added an answer on June 17, 2026 at 12:22 pm

    I think this:

     $serial = intval($_GET['serial']);
    $query = "SELECT serial, name, desription FROM product_list WHERE serial = {$serial}"; 
    
    echo "{$row[name]}";
    

    Should be this:

        $serial = intval($_GET['code']);
    $query = "SELECT serial, name, desription FROM product_list WHERE serial = '".$serial."'"; 
    echo $row['name'];
    

    In the above you assign the query but you will still need to execute the query to get a result.

    And this will not work to pass $_GET:

     a href="show.php?code=$row['serial']|$row['name']
    $row['description']
    

    If you are learning DO NOT start by using mysql….. Use mysqli or PDO

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