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Home/ Questions/Q 8581329
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T21:01:16+00:00 2026-06-11T21:01:16+00:00

I have been working with regular expressions for the past couple days in class.

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I have been working with regular expressions for the past couple days in class. I cannot determine why this expression doesn’t work. I am looking for expressions like the following:

value = (struct node){ 5, NULL};
value2 = (structname){ 1, 2 }; 
*pointer = ( bla ){3,4};

Here is the expression I am using:

sed -n '/^[*0-9A-Za-z_]+ *= *( *[0-9A-Za-z_]+ *[0-9A-Za-z_]* *) *{[0-9A-Za-z, ]};/p'     structfile

What am I missing because it returns nothing. Also a side note I have used [^,] in some expressions and I still get lines with , s. What am I missing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T21:01:17+00:00Added an answer on June 11, 2026 at 9:01 pm

    You need to escape +; and fix {[0-9A-Za-z, ]} to {[0-9A-Za-z, ]*}.

    sed -n '/^[*0-9A-Za-z_]\+ *= *( *[0-9A-Za-z_]\+ *[0-9A-Za-z_]* *) *{[0-9A-Za-z, ]*};/p' structfile
    
    
    me@localhost:~$ cat structfile 
    value = (struct node){ 5, NULL};
    value2 = (structname){ 1, 2 }; 
    *pointer = ( bla ){3,4};
    not astruct
    notastructstr =
    
    me@localhost:~$ sed -n '/^[*0-9A-Za-z_]\+ *= *( *[0-9A-Za-z_]\+ *[0-9A-Za-z_]* *) *{[0-9A-Za-z, ]*};/p' structfile
    value = (struct node){ 5, NULL};
    value2 = (structname){ 1, 2 }; 
    *pointer = ( bla ){3,4};
    
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