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Home/ Questions/Q 8129413
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T08:18:08+00:00 2026-06-06T08:18:08+00:00

I have below code: class Program { static void Main(string[] args) { Task[] tasks

  • 0

I have below code:

class Program
{
    static void Main(string[] args)
    {

        Task[] tasks = new Task[3]
                        {
                            Task.Factory.StartNew(() => Console.WriteLine("Hello A")),
                            Task.Factory.StartNew(() => Console.WriteLine("Hello B")),
                            Task.Factory.StartNew(() => Console.WriteLine("Hello C"))
                        };
        Task.WaitAll(tasks); 
        Console.WriteLine("Hi ABC");
    }
}

I build and run the above code, it gives output:
Hello C
Hello B
Hello A
Hi ABC

But if I comment Task.WaitAll(tasks), one of the outputs is:
Hi ABC
Hello B
Hello C

Does it mean when Console.WriteLine(“Hi ABC”) finishes execution, thread which executes Console.WriteLine(“Hello A”) didn’t get a chance to finish execution?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T08:18:10+00:00Added an answer on June 6, 2026 at 8:18 am

    Yes, that’s correct. Your main thread is terminating the process before the child threads have finished – or started in some cases. If you don’t do something to keep the main thread busy, then when the main thread terminates (after “Hi ABC”), the process termination will kill all outstanding threads. If the A thread (or any of the child threads) hasn’t been scheduled yet, then it won’t have a chance to output at all.

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