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Home/ Questions/Q 8674923
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T19:49:32+00:00 2026-06-12T19:49:32+00:00

I have changed my code, according to the reccommendations to my previous question. Now,

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I have changed my code, according to the reccommendations to my previous question. Now, i have the following code:

char* id = someFunction();      
if (strcmp(id,"0x01") == 0) {
    unsigned char cbuffer[]={0x01, 0x00};
    id=reinterpret_cast<char*>(cbuffer);
}

My question – is it the correct approach, to pass the {0x01, 0x00} to the id of type char*? And the second question is – how to free the id pointer after?

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  1. Editorial Team
    Editorial Team
    2026-06-12T19:49:33+00:00Added an answer on June 12, 2026 at 7:49 pm

    The code you have posted is dangerous as you are passing a pointer to storage that is in automatic scope. The buffer will be trashed when it leaves scope (the scope of the if in this case).

    Instead try something like this:

    id = strdup((char*)cbuffer);
    

    or even better you could use escape sequences and avoid having to specify the char values yourself:

    id = strdup("\x01");
    

    You can then free the memory used by this string by using free.

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