Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 9201375
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 17, 20262026-06-17T22:59:30+00:00 2026-06-17T22:59:30+00:00

I have checked my edittext is visible or invisible in android. Now i have

  • 0

I have checked my edittext is visible or invisible in android.

Now i have to check the condition is.,

  1. If my edittext is visible means how can i insert the data.
  2. If my edittext is gone means how can i insert on another data.

This is my code for if i have to check the checkbox means the edittext is invisible otherwise the edittext is visible .:

 chkIos = (CheckBox) findViewById(R.id.addresscheckbox);
        
    chkIos.setOnClickListener(new View.OnClickListener() {
      public void onClick(View v) {
        if (((CheckBox) v).isChecked())
        {
             S_address = (TextView)findViewById(R.id.address1);  
             S_address.setVisibility(View.GONE);  
          
        Saddress = (EditText)findViewById(R.id.tf_address1);  
        Saddress.setVisibility(View.GONE);  
      }
        else
        {
             S_address = (TextView)findViewById(R.id.address1);  
             S_address.setVisibility(View.VISIBLE);  
          
       Saddress = (EditText)findViewById(R.id.tf_address1);  
        Saddress.setVisibility(View.VISIBLE);
        if(!(Saddress.getText().toString().length() == 0)){
            
                showAlertbox(" Shipping Address is Required!!"); 
            }
      }

The below code is ., if my edittext is visible means insert the saddr value.otherwise insert the baddr value.how can i check the condition.

Here below error is showing:
VISIBLE cannot be resolved to a variable.

      if(Saddress== VISIBLE)
    {
        PropertyInfo saddress =new PropertyInfo();
        saddress.setName("Saddress");//Define the variable name in the web service method
        saddress.setValue(saddr);//Define value for fname variable
        saddress.setType(String.class);//Define the type of the variable
        request.addProperty(saddress);//Pass properties to the variable
        
    }
    else
    {
    PropertyInfo saddress =new PropertyInfo();
    saddress.setName("Saddress");//Define the variable name in the web service method
    saddress.setValue(baddr);//Define value for fname variable
    saddress.setType(String.class);//Define the type of the variable
    request.addProperty(saddress);//Pass properties to the variable
    }

please see the full source code here:full code

EDIT:

In my code i have to check the checkbox means the Saddress is invisible know.that time i have to click the button means the baddr value is inserted…If i have to uncheck the checkbox means the Saddress value is visible.that time i have to insert the saddr value.

Here i have to run the app means the baddr value is insered both Saddress==visible and Saddess==invisible case.how can i write the condition for these.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-17T22:59:31+00:00Added an answer on June 17, 2026 at 10:59 pm

    use

    if(Saddress.getVisibility() == View.VISIBLE){
      //.. your code here
    }
    

    instead of

    if(Saddress== VISIBLE){
    //.. your code here
    }
    

    because VISIBLE,GONE and INVISIBLE is part of View class instead of Activity

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have checked out now a local working copy of a codebase that lives
I'm developping an android app , and i have an EditText and a two
I have checked everywhere and I can't seem to locate the problem. The compiler
I have checked all these articles, and I still can't figure out why I
I have an EditText with android:inputType=phone keybord. There is an OK on this keyboard.
I have checked the memory whilst sending and receiving data over one connection, and
I have checked some examples on internet but I can't get my (first) batch
I have checked all posts here, but can't find a solution for me so
Have checked some backbone.js tutorials and can't understand how to get model id from
I have checked some other examples. I am working on a WinForm. & now

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.