Question

I have class and this class contains a number. And I have a vector contains object pointer of class. And I want to sort that objects according to their numbers. How can I do this?
Thanks for answers.

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

class Course
{
public:
    Course (int code, string const& name) : name(n), code(c) {}
    int getCourseCode() const { return code; }
    string const& getName() const { return name; }

private:
    string name;
    int code;
};

int main()
{
    vector<Course*> cor;
    vector<Course*>::iterator itcor;

    cor.push_back(new Course(3,"first"));
    cor.push_back(new Course(2,"sekond"));
    cor.push_back(new Course(4,"third"));
    cor.push_back(new Course(1,"fourth"));
    cor.push_back(new Course(5,"fifth"));  
    sort (cor.begin(), cor.end());
    for (itcor=cor.begin(); itcor!=cor.end(); ++itcor) {
        cout << *itcor << ' ';
    }
}

For example when I want the sort the objects they are being sorted according to their adresses.

Answer 1

You can do this in three ways:

1) Overload the < operator, and call std::sort algorithm. The code will look like this:

bool operator<(Course *a, Course *b) const {
  // do comparison
  return A_BOOL_VALUE;
}

std::sort(array_of_courses.begin(),array_of_courses.end());

The first way is wrong, as you can’t overload the < operator in pointers.

2) Create a compare function, and then call the second version of std::sort. The code looks like this:

bool compare(Course *a,Course *b) {
  // do comparison
  return A_BOOL_VALUE;
}

std::sort(array_of_courses.begin(),array_of_courses.end(),compare);

3) Create a compare class, which has it’s () operator overloaded, and then call the third verion of std::sort. The code:

struct Compare {
  bool operator()(Course *a, Course *b) {
    // do comparison
    return A_BOOL_VALUE;
  }
};

std::sort(array_of_courses.begin(),array_of_courses.end(),Compare);

Note: the sort function is found at the algorithm header file.