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Home/ Questions/Q 8675669
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T20:00:30+00:00 2026-06-12T20:00:30+00:00

I have ClassA: public class ClassA<T> I have a generic method in ClassA: protected

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I have ClassA:

public class ClassA<T>

I have a generic method in ClassA:

protected TP FunctionA<TP>(Expression<Func<T, TP>> p)
{
    //Code for method here
}

ClassB derives from ClassA:

public class ClassB : ClassA<ClassB>

ClassC derives from ClassB:

public class ClassC : ClassB

When creating ClassC like in the example above, ClassA will still have a type of ClassB because ClassC derives from ClassB, and ClassB is what sets the type of ClassA to ClassB.

What I am wondering is how do I derive from ClassB while at the same time setting ClassA type to ClassC and also ClassB still needs to be able to be used on its own without needing to derived from.

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-12T20:00:31+00:00Added an answer on June 12, 2026 at 8:00 pm

    ClassB is no longer generic. Nor is ClassC. If you want to keep it generic then the pattern is:

    class ClassB<T> : ClassA<T> {}
    class ClassC<T> : ClassB<T> {}
    
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