Question

I have code like this:

def a = [".15", "7..", "402", "..3"]
c = a.permutations() as List
println c[0].join()

Which outputs 7....3402.15. In this one, I need to get only numbers, i.e 7,3402,15. Even more notably I need there sums i.e in our example we would get 7,9,6.

How this can be done in groovy?

Answer 1

As a quick response, one solution would be:

def result = [".15", "7..", "402", "..3"].permutations()*. 
  join()*.                                 // Join each permutation together into a single string
  split( '\\.' )*.                         // Split each of these Strings on the '.' char
  findAll()*.                              // Remove empty elements (where we had '..' before splitting)
  collect { it -> it*.toInteger().sum() }  // Convert each String to List<Integer> and sum