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Home/ Questions/Q 614827
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:09:12+00:00 2026-05-13T18:09:12+00:00

I have code like this: setTimeout(foo, 600); I always thought that foo didn’t take

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I have code like this:

setTimeout(foo, 600);

I always thought that foo didn’t take any arguments, e.g.:

function foo() { /* bars */ }

However, doing the following:

function foo(a) { alert(a); /* bars */ }

Popped up an alert displaying -7. What does this number represent?

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:09:13+00:00Added an answer on May 13, 2026 at 6:09 pm

    It is the time difference (in milliseconds) from when it was scheduled to run it and when it actually ran.

    alert(setTimeout(function(a) { alert(a) }, 2000));
    

    If you clear the first alert in time, you will see the next alert is somewhere -10 to 10. If you wait a few seconds, you will see something that is around the time you waited minus 2000.

    The same thing can be seen for setInterval. Run the following in Firebug:

    setInterval(function(a) { alert(a); }, 2000);
    

    Try closing the alert quick, it will be around 0 again. Leave it open – it will give you a large value.

    Note This is on Firefox Mac, where keeping an alert open will halt processing of Javascript, so the timer does not execute until I close the alert. The behavior of the tests above may be different in other browsers

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