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Home/ Questions/Q 8056623
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T08:46:10+00:00 2026-06-05T08:46:10+00:00

I have code resembling the following: try{ func1(); } catch(Exception e){ /Do something }

  • 0

I have code resembling the following:

try{
    func1();
}
catch(Exception e){
    /Do something
}


static func1(){
    func2();
}

static func2(){
    //Exception thrown here
    System.IO.StreamReader file = new System.IO.StreamReader(filePath);
}

when an exception is thrown by the line of code in func2() I get no notification in the catch clause. I do not explicitly throw anything, I just have regular function declarations which are static- no “throw” appears anywhere.

Why isn’t the exception propagating upwards to the catch statement??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T08:46:14+00:00Added an answer on June 5, 2026 at 8:46 am

    An exception will ‘bubble up’ until it is caught or crashes your app.

    Your best bet is to use the Debugger. Make sure you have it set to stop on HANDLED exceptions (Debug / Exceptions / Check the ‘Thrown’ box on the Common Language Runtime Exceptions).

    Now run your code. If func2 throws an exception – your code will break; regardless of whether or not it is handled. You can step through the code and see what is handling it.

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