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Home/ Questions/Q 7421501
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T08:25:11+00:00 2026-05-29T08:25:11+00:00

I have code that generates a random number form 0-1 3 times and I

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I have code that generates a random number form 0-1 3 times and I need it to be added to a variable so it turns into a binary number.So, in theory, this would run three times and possibly give me 101;

String storage = null;
        int i = 0;
        while (i < 3) {
            int binny = this.giveMeBinary();
            storage.concat(String.valueOf(binny));
            i++;
        }

        int ans = Integer.parseInt(storage);

But when I try and run this I get the NullPointerException error for storage. Is there a way to just “add” a string to the variable?

the method giveMeBinary just returns a 0 or a 1.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T08:25:12+00:00Added an answer on May 29, 2026 at 8:25 am

    Your problem is that you are initializing the string to null. Doing something like so should solve your problem:

            String storage = "";
            int i = 0;
            while (i < 3) {
                int binny = this.giveMeBinary();
                storage += (String.valueOf(binny));
                i++;
            }
    
            int ans = Integer.parseInt(storage);
    

    However, concatenating strings in such a manner is not recommended. What you can do is use a StringBuilder like so:

            StringBuilder storage = new StringBuilder();
            int i = 0;
            while (i < 3) {
                int binny = this.giveMeBinary();
                storage.append(String.valueOf(binny));
                i++;
            }
    
            int ans = Integer.parseInt(storage.toString());
    
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